Sunday, September 16, 2012
Practice for finding the other trig functions and the angle from the value of sine, cosine or tangent, assuming all are positive
Example #1: cosalpha = 2/5
(2/5)² + sin²alpha = 1
4/25 + sin²alpha = 1
sin²alpha = 21/25
sinalpha = sqrt(21)/5
since we have sine and cosine, tan = sin/cos.
tanalpha = [sqrt(21)/5]/[2/5] = sqrt(21)/2
With this editor, I can't write -1 as a superscript, so instead I will use the words arcsine, arccosine and arc tantangent. On your calculator, arccos(2/5) = 66.42182152...°, which we round to 66.4218°.
If you take the unrounded value and change it to degrees-minutes-seconds, rounding the seconds to the nearest whole number, we get 66° 25' 19".
Example #1.1: If we had sinalpha = 2/5, the work would look nearly identical, except cosalpha would equal sqrt(21)/5. Tangent of this angle is the reciprocal of sqrt(21)/2, which is 2sqrt(21)/21 when written in rational denominator form. The angle is the complement of our original angle, which means they add up to 90°. arcsin(2/5) = 23.57817848...°, which rounds to 23.5782°.
The DMS version of the unrounded value, rounded to the nearest whole second is 23° 34' 41".
Example #2: tanbeta = 2/5
Since tan = sin/cos,
tan × cos = sin
Using this, cos²beta + (2/5)²cos²beta = 1
cos²beta + 4/25cos²beta = 1
29/25cos²beta = 1
cos²beta =25/29
cosbeta = sqrt(25/29) = 5/sqrt(29) = 5sqrt(29)/29
arctan(2/5) = 21.80140949...°, which rounds to 21.8014°, and in DMS is 21° 48' 5".
Here are practice problems. Get the other two trig values, the angle rounded to the nearest ten thousandth of a degree and rounded to the nearest second in DMS mode.
1) cosalpha = 1/10
2) tanbeta = 1/10
3) singamma = 1/9
4) tandelta = 1/9
Answers in the comments.
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1) cos(alpha) = 1/10
ReplyDeletesin(alpha) = sqrt(99)/10 = 3sqrt(11)/10
tan(alpha) = 3sqrt(11)
arccos(1/10) = 84.26082952...°,
rounds to 84.2608°,
converts to DMS of 84° 15' 39"
2) tan(beta) = 1/10
cos(beta) = sqrt(100/101) = 10/sqrt(101) = 10sqrt(101)/101
sin(beta) = sqrt(101)/101
arctan(1/10) = 5.710593137...°,
rounds to 5.7106°,
converts to 5° 42' 38"
3) sin(gamma) = 1/9
cos(gamma) = sqrt(80)/9 = 4sqrt(5)/9
tan(gamma) = 1/4sqrt(5) = sqrt(5)/20
arcsin(1/9) = 6.379370208...°
rounds to 6.3794°,
converts to 6° 22' 46"
4) tan(delta) = 1/9
cos(delta) = sqrt(81/82) = 9/sqrt(82) = 9sqrt(82)/82
sin(delta) = sqrt(82)/82
arctan(1/9) = 6.340191746...°
rounds to 6.3402°
converts to 6° 20' 25"
Note: If we have a number x close to zero, the inverse tangent and inverse sign of x will be very close to each other. This is because tangent = sine/cosine and if sine is almost zero, cosine is almost 1.